Esther G. answered 02/15/23
MIT Physics Graduate with 5+ Years Experience Tutoring MCAT Physics
Hi Diane!
Hopefully you've already seen that this problem is one of non-constant acceleration, and since you're in an algebra-based course, this means you can't use kinematics for (a). Let's try using energy instead!
Is energy conserved in this problem? Yes, since there are no none-conservative forces at play. Therefore, if we consider state A to be at 1000km and B to be at the surface:
EA = UG, A + KEA = UG, B + KEB
When solving this equation, we want to use UG = -GMmoonmmeteor/r, not mgh - because acceleration due to gravity will vary over this large scale! And crucially, for state A, r = radius of moon + 1000 km, since r is measured from the center of the moon.
Once you have solved for part (a), note that the moon brings the meteor to rest, so it does negative work equal to the object's kinetic energy upon impact (by the work-kinetic energy theorem).
Hope this helps!