Write an equation in slope-intercept form of the line that passes through (-9,5) and (-3,3)

Answer 1

Slope-intercept form: y = mx + b (m is slope; b is y-int).

slope = rise/run = (y₂ - y₁)/(x₂ - x₁) = (3 - 5)/(-3-(-9)) = -2/6 = -1/3

Using point (-3,3): 3 = -(1/3)(-3) + b → 3 = 1 + b → b = 2

So equation is y = -(x/3) + 2

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Answer 2

Hello, thank you for taking the time to post your question!

The general form that we’re after here is y = mx + b, but in order to get it in that form we need to find both the slope(m) and y-intercept(b) values with the points given. For the points given that means

m = (y2 – y1) / (x2 – x1) = (3-5)/(-3 - -9) = -2/6 = -1/3

Then to find b we can take

y = -1/3x + b and plug in one of the given points

3 = -1/3(-3) + b

3 = 1 + b

2 = b

Putting it all together then makes the final equation

y = -1/3x + 2

I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)

Answer 3