Carissa C. answered 01/25/23
Compassionate Tutor Specializing in Early Algebra and Proofreadin
First, make two equations. Let X represent the jam and Y represent the bread mix. Since we know there are 8 items total, let the first equation show the number of items. X+Y=8. Next, let the second equation show the cost of the items. The jam (X) costs $6 and the bread mix (Y) costs $5. The total cost is $45. So the second equation is 6X+5Y=45. Use the substitution method to solve.
X+Y=8
6X+5Y=45
First, isolate X in the first equation, to make it X=8-Y
Now, substitute that for X in the second equation. 6(8-Y)+5Y=45
- Multiply each term in the parenthesis by 6. 48-6Y+5Y=45. Now combine like terms.
- 48-Y=45. Subtract 48 from each side
- -Y=-3. Multiply both sides by -1 to make it positive
- Y=3
Now, substitute 3 for Y in the first equation.
X+3=8. Subtract 3 from both sides
X=5
Now check your work. Plug the numbers into both equations to see if it's true.
5+3=8
6(5)+5(3)=45