Slope-intercept form equation

Question

A line passes through the point (-9, 8) and has a slope of 2/3 write an equation in slope-intercept form for this line

Answer 1

Raymond B. has already posted a correct answer. I'll only add a few details as we approach the solution a little differently.

The slope-intercept form of an equation is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = zero).

We are given the slope, m, as (2/3), so we can quickly write y = (2/3)x+b.

Now we need a value of b such that the line is shifted so that it crosses point (-9,8). This can be found by entering (-9,8) into the above equation and solving for b:

y = (2/3)x+b

8 = (2/3)*(-9)x+b for (-9,8)

8 = -6+b

b = 14

The equation becomes y = (2/3)x + 14

Answer 2

y-8 = (2/3)(x+9)

y = (2/3)x + (2/3)(9) +8

y= (2/3)x +6 + 8

y = (2/3)x + 14 in slope intercept form y intercept = 14 = the point (0, 14)