Arthur D. answered 01/02/23
Mathematics Tutor With a Master's Degree In Mathematics
Here's another way to look at the problem.
adults 20 dirs
children 15 dirs
20+15=35
105/35=3
3 adults and 3 children
If the total cost was 120, then 120/35=3 R15.
3 adults, 3 children plus another child for a total of 3 adults and 4 children
If the total cost was 145, then 145/35=3 R40
3 adults, 3 children plus 2 more adults for a total of 5 adults and 3 children
It gets complicated when the cost gets higher and higher such as 160 dirs whereby you have 2 possible solutions. Give it a try.
Using 2 variables forces trial and error just like a large enough increase in price.