A football player kicked a football ball at 31 meters/second at an angle of 50° from the ground.

Question

1. What is the flight time of the ball?
2. What is the range of the kick?
3. What is the maximum height of the kick?

Answer 1

1. y = 31sin50°t - 4.9t² = 0; t = 0(moment of kick) or t = 31sin50°/4.9 = 4.85 s
2. Range x = 31cos50°·4.85 = 96.64 m
3. v_y = 31sin50° - 9.8t = 0; t = 31sin50°/9.8 = 2.42 s

Maximum height y = 31sin50°·2.42 - 4.9·2.42² = 28.77 m