A bomber flying horizontally at 120 meters/second drops a bomb from an altitude of 240 meters.

Question

1. How long does it take for the bomb to hit the ground?

Answer 1

Assuming the bomb moves with constant 2D acceleration (0, –g), by time-integration its velocity is (v₀, –gt) and its position is (v₀t, y₀ – gt²/2). Therefore for any v₀, y → 0 as t → √(2y₀/g).