A minor league baseball team plays 91 games in a season. If the team won 15 more than 3 times as many games they lost, how many wins and losses did the team have?

Answer 1

Hello, thank you for taking the time to post your question!

The key on this type of question is to set up a system of equations based on the information given! If you use “W” to represent the number of wins and “L” to represent the number of losses, for this one that would mean  

W + L = 91

W = 3L + 15

From there then you can solve algebraically for the values! I would plug in W = 3L + 15 into the first equation

3L + 15 + L = 91

4L = 76

L = 19, so the team lost 19 games

W = 3(19) + 15 = 57 + 15 = 72, so the team won 72 games

I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

L + W = 91

W = 3L + 15

Substitute: L + 3L + 15 = 91

4L = 76

L = 19 losses

W = 91 - 19 = 72 wins

Answer 3

Hi Celeste,

The team won a total of 72 games and lost a total of 19 games.

72 + 19 = 91 games played total

19 games lost x 3 = 57

57 + 15 = 72 games won