The admission fee at an amusement park is $1.50 for children and $6.80 for adults. On a certain day, 301 people entered the park, and the admission fees collected totaled $1008.

Question

Write two equations given the following information. You may use the variables xx and yy. Then solve the system to find how many children and how many adults were admitted to the amusement park.

The admission fee at an amusement park is $1.50 for children and $6.80 for adults. On a certain day, 301 people entered the park, and the admission fees collected totaled $1008.

Number of Children Equals: __________

Number of Adults Equals: ____________

Answer 1

Let x = number of children and y = number of adults (I don't see why they'd be doubled).

Then x + y = 301 [Eqn A], the people in the park.

Also, we need to multiply admission cost by number of people in an age group to get the days admission fees...1.5x + 6.8 = 1008 [Eqn B].

So we have this system of equations to solve:

A] x + y = 301

B] 1.5x + 6.8 = 1008

I used the Substitution Method.

A] x = 301 - y

B] 1.5(301-y) + 6.8y = 1008

451.5 + 5.3y = 1008

5.3y = 1008 - 451.5

5.3y = 556.5

y = 105, the number of adults

A] x = 301 - y

x = 301 - (105)

= 196, the number of children

Always check your solution by plugging the answer you get into the ORIGINAL statement/equation!!

I leave that up to you. :)

Answer 2

x is number of children, then (301 - x) is number of adults.

Then we have: 1.50x + 6.80(301 - x) = 1008;1.50x - 6.80x = 1008- 2046.80; - 5.3x = - 1038.8;

x = 196 children and 301 - 196 = 105 adults