How do you write an equation of the parabola that passes through the point (1,5) and has x intercepts 2 and 6?

Answer 1

y=a(x-2)(x-6)

5=a(1-2)(1-6)

a=1

y=x^2-8x +12 in standard form

or

y= (x-4)^2 -4 in vertex form

or

y=(x-2)(x-6) in x intercept form