Help needed with physics problem

Question

A 2.5-cm-diameter parallel-plate capacitor has a 2.1 mm spacing. The electric field strength inside the capacitor is 1.0×10^5 V/m .

How much charge is on each plate?

My answers were:

6.0*10^-8 C

6.95*10^11 C

0.0011 C and

5.5*10^-10 C, all of which were incorrect.

thanks for your help

Answer 1

I assume that this means that the plates have an area of πd²/4 = π(.025m)²/4 = 4.9087 x 10^-4 m²

I also assume that the capacitor can be considered an infinite plate capacitor.

C = ε₀A/d

Q = CV = CEd = ε₀EA = 8.854 x 10^-12(10⁵)(.4.9087 x 10^-4) = 4.35 x 10^-10 Coulombs

Not a previous answer at least... Make sure that they ask for coulombs and not nanocoulombs.

Please consider a tutor. Take care.