J.R. S. answered 09/19/22
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
∆E = RH (1/nf2 - 1/ni2)
∆E = change in energy = ?
RH = -2.179x10-18 J
nf = final energy level = 1
ni = final energy level = 6
∆E = -2.179x10-18 J (1 - 0.02778) = -2.179x10-18 J (0.9722)
∆E = -2.12x10-18 J