Inactive Tutor answered 09/18/22
x / 4 = sin t
x2 / 16 = sin2 t
x2 / 16 = 1 - cos2 t
y / 4 = cos t
y2 / 16 = cos2 t
x2 / 16 = 1 - (y2 / 16)
(x2 / 16) + (y2 / 16) = 1
x2 + y2 = 16
Same result if sin was substituted for cos
Nicholas K.
asked 09/18/22A pair of parametric equations is given below.
x = 4 sin(t), y = 4 cos(t), 0 ≤ t ≤ 𝜋
Find a rectangular-coordinate equation for the curve by eliminating the parameter.
My answer is y=sqrt ((4+x)(4-x)) but it is incorrect.
Inactive Tutor answered 09/18/22
x / 4 = sin t
x2 / 16 = sin2 t
x2 / 16 = 1 - cos2 t
y / 4 = cos t
y2 / 16 = cos2 t
x2 / 16 = 1 - (y2 / 16)
(x2 / 16) + (y2 / 16) = 1
x2 + y2 = 16
Same result if sin was substituted for cos
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