One number is 6 more than another. Their product is 520. Find the numbers.

Question

pls help me i don't understand it!!! T^T

Answer 1

Hi,

One number is 6 more than another. Their product is 520. Find the numbers.

number = x another = y

1) x = 6 + y AND 2) x.y = 520 then replace x in second equation

:

( 6+ y ) .y = 520 now solve it

y² + 6 y - 520 = 0 =====> y = 20, y = -26 not acceptable

when y = 20 ---> x = 6 + 20 = 26

numbers are 20 , 26

I hope it is useful.

Minpp

Answer 2

You asked for help solving: "One number is six more than another. Their product is 520."

Let's translate these words into an equation:

One number (n) is six more than another (x).

n = 6+x

Their product is 520.

n•x=520

We now have two equations, each of which has two variables. We need to find a way to eliminate one of the variables in order to start solving. One way to do this is with substitution.

n•x=520

From the first equation that we wrote, we know that n = 6+x.

Where you see n in the second equation, you can substitute 6+x because they have equal values.

n•x=520

(6+x)•x=520

Now this is a solvable one-variable equation

First, simplify the left side of the equation

6x+x²=520

Then you might notice that we can re-write this equation in the format ax² + bx + c = 0, which tells us it is a quadratic equation that can be solved for x.

x² + 6x – 520 = 0

a = 1

b = 6

c = -520

Substitute these values into the quadratic formula or solve by factoring to find the possible values of x.

Hope this helps! If you find this answer useful, please give it an upvote.

Answer 3

Let x = first number

Let y = second number, since it is 6 more than the other, I can write it like x+6

Their product is 520

x(x+6)=520

Can you solve from there?