Help me solve this

Question

You prepared a saturated solution of copper(I) chloride (Ksp = 1.248x10^-6) in pure water. What are the

concentrations of Cu+1(aq) and Cl-1(aq) ions in the saturated solution?

Answer 1

Copper(I) chloride = CuCl

CuCl(s) <==> Cu⁺(aq) + Cl^-(aq)

Ksp = [Cu⁺][Cl^-]

1.248x10^-6 = (x)(x)

x² = 1.248x10^-6

x = 1.12x10^-3 M = [Cu⁺] = [Cl^-]

NOTE: In a previous question where the solution also contained the common ion Cl-, the concentration of Cu+ was only 2.99x10^-5 M. So, you can now see how the presence of a common ion will DECREASE the solubility of the salt because of LeChatelier's principle.