help solving this

Question

Found the following:

Pb+2(aq) + 4 I-(aq) <=> [PbI4]-2(aq)

K = (3.062x10^4)

What is the value of K for the following reaction?

3 Pb+2(aq) + 12 I-(aq) <=> 3 [PbI4]-2(aq)

Answer 1

Original reaction: Pb²⁺(aq) + 4I^-(aq) ==> PbI₄^2-(aq) ... K = 3.062x10⁴

Other reaction: 3Pb²⁺(aq) + 12I^-(aq) ==> 3PbI₄^2-(aq) ... K = ?

Since the "other reaction" is 3x the original, the K value will be the original K value cubed.

Thus K = (3.062x10⁴)³

K = 2.87x10¹³