What is the value of K for the following reaction?

Question

The following found below:

HNO2(aq) + H2O(l) <=> H3O+(aq) + NO2-(aq)

K = (4.552 x 10^-4)

What is the value of K for the following reaction?

H3O+(aq) + NO2-(aq) <=> HNO2(aq) + H2O(l)

Answer 1

The 2nd reaction is the REVERSE of the original reaction. When a reaction is reversed, the K value for the new reaction is the inverse of the K value of the original reaction.

Thus, K for H3O+(aq) + NO2-(aq) <=> HNO2(aq) + H2O(l) = 1 / 4.552x10^-4

K = 2197