How do find H3O+ and OH??

Question

1.) The pOH of an aqueous solution at 25°C is (4.032x10^0). What is [OH-]?

2.) An aqueous solution at 25°C pH is (5.897x10^0). What is [H3O+]

Answer 1

pOH = -log[OH-]

[OH-] = 1x10^-pOH

[OH-] = 1x10^-4.032

[OH-] = 9.300x10^-5 M

pH = -log [H3O+]

[H3O⁺] = 1x10^-pH

[H3O⁺] = 1x10^5.897

[H3O⁺] = 1.268x10^-6 M