What is the value of Kc for this reaction?

Question

A(aq) + 2 B(aq) ↔ C(aq) + D(aq)

The reaction reaches equilibrium, and [A]eq=0.282M, [B]eq=0.318M, [C]eq=0.732M, and [D]eq=0.836M . What is the value of Kc for this reaction? (Report your answer to 2 decimal places.)

Answer 1

A(aq) + 2 B(aq) ↔ C(aq) + D(aq)

Kc = [C][D] / [A][B]²

Kc = (0.732)(0.836) / (0.282)(0.318)²

Kc = 0.612 / 0.0285

Kc= 21.5