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Question

You have a stock solution of glucose that has a concentration of 1.539M which you will use to prepare a series of dilutions. Preparing “Solution A”, you use 29.31mL of the stock solution and dilute it to 60.00mL with water. Preparing “Solution B”, you use 18.96mL of “Solution A” and dilute it to 45.00mL with water. Preparing “Solution C”, you use 32.41mL of “Solution B” and dilute it to 60.00mL with water. What are the concentrations of solutions A, B, and C?

Answer 1

V1M1 = V2M2

V1 = initial volume

M1 = initial molarity

V2 = final volume

M2 = final molarity

Solution A

(29.31 ml)(1.539 M) = (60.00 ml)(x M)

x = 0.7518 M

Solution B

(18.96 ml)(0.7518 M) = (45.00 ml)(x M)

x = 0.3168 M

Solution C

(32.41 ml)(0.3168 M) = (60.00 ml)(x M)

x = 0.1711 M