The fast way is to realize that the inertia of rotation for the sphere contributes .4m and the period can be written as T = 2πsqrt(1.4m/k). The sphere has more inertia than an ice puck of mass m because of its rotational inertia. Full-fledged:
Rotation: torque = FfR = Iα = .4mR2α = 0.4 mRa (because a=Rα), so Ff = .4ma
Translation: Fnet = -kx + Ff = ma or -kx = 1.4ma (which is just the standard SHM problem with a mass of 1.4m which we can put into the T equation.
In the standard form: d2x/dt2 = - (k/1.4m)x where ω = sqrt(k/1.4m) is the angular frequency.
2π/ω = T
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