Can you help me with this question

Question

The perimeter of a rectangular painting is 308 cm . If the length of the painting is 86 cm what is its width?

Answer 1

Perimeter of a rectangle is (length plus width) x 2 = 308.

So to find (length plus width) we need to divide 308 by 2

308/2 = 154 = length plus width = 86 + width

Finally to find width we need to subtract 154 - 86 = 68

Answer 2

The perimeter of a rectangular painting is 308 cm . If the length of the painting is 86 cm what is its width?

Perimeter is the distance around a rectangle. It can be written as 2L+2W

Is the length is 86 you would write:

2(86)+2W=308

172+2W=308

2W=308-172

From here, solve for W.

Answer 3

Or, P = 2L + 2W

308 = 2(86) + 2W

308 = 172 + 2W -> 308 - 172 = 2W

136 = 2W

W = 136/2 = 68 cm