Raymond B. answered 03/18/22
Math, microeconomics or criminal justice
3^0 = 1
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 81x3 = 243
3^6 = 243x3 =729
3^7 = 729x3 = 2227
3^8 = 2227x3 = 6681
278885/4 = 69721 with remainder 1
3^278885 has the same last digit as 3^8, 3^4 and 3^1 = 3
if the exponent is exactly divisible by 4, the last digit is 1
if the exponent is divisible by 4 with remainder 1, then the last digit is 3
if the exponent is divisible by 4 with remainder 2, the last digit is 9
if the exponent is divisible by 4 with remainder 3, the last digit is 7
the pattern repeats for the last digit every 4 times the exponent increases by 1
1, 3, 9, 7, 1, 3, 9, 7, 1,3, 9, 7, ....
a) 3 You're correct