
Douglas C. answered 03/10/22
Retired Harvard Environmental Physics Prof
Assume that "winning" means getting one or more of the prizes.
You have about [(10)/(1,100,000)](44,020) = 40% probability of winning a prize from at least one of your tickets.
You odds on the ten-ticket bet are
P(win)/P(lose) = (0.4)/(1-0.4) = 0.4/0.6 = 2:3 .