A silver chloride sample was allowed to dissociate in 15 ml of water.

Question

What is the chloride ion concentration if the sample weighs 0.5479 g?

Answer 1

AgCl = silver chloride

molar mass = 143.3 g/mol

Convert 0.5479 g AgCl to moles

0.5479 g x 1 mol / 143.3 g = 0.003823 moles AgCl

Volume = 15 ml x 1 L / 1000 ml = 0.015 L

molar concentration = 0.003823 mols / 0.015 L = 0.25 M (to 2 sig. figs.)

NOTE: AgCl is not very soluble, but since the problem doesn't supply the solubility nor the Ksp, we can't really determine the final concentration of AgCl, but it will be considerably less than 0.25 M