What would the outcomes be of AaBbCc x aabbcc?

Question

I am not sure how to do this but need to know how to for my upcoming test in class.

Answer 1

In a simple Mendelian cross, each trait in inherited independently of any other (Law of Independent Assortment). So for each:

Aa x aa --> Aa and aa (1:1)

Bb x bb --> Bb and bb (1:1)

Cc x cc --> Cc and cc (1:1)

All together by multiplying all the individual outcomes:

(Aa , aa) x (Bb, bb) x (Cc, cc) =

(AaBb, Aabb, aaBb, aabb) x (Cc, cc) =

(AaBbCc, AabbCc, aaBbCc, aabbCc, AaBbcc, Aabbcc, aaBbcc, aabbcc) all (1:1:1:1:1:1:1:1) ratio.