J.R. S. answered • 03/08/22
Tutor
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Ph.D. in Biochemistry with an emphasis in Neurochemistry/Neuropharm
Na2SO4(aq) + Ba(NO3)2(aq) ==> 2NaNO3(aq) + BaSO4(s) ... balanced equation
molar mass BaSO4 = 233 g/mol
3.09 g BaSO4 x 1 mol / 233 g = 0.0133 moles BaSO4
moles Ba(NO3)2 = 0.0133 mols BaSO4 x 1 mol Ba(NO3)2 / mol BaSO4 = 0.0133 molsBa(NO3)2
Volume of Ba(NO3)2 = 53 ml x 1 L / 1000 ml = 0.053 L
Molar concentration of Ba(NO3)2 = 0.0133 mols / 0.053 L = 0.25 M
