
David B. answered 02/22/22
Math and Statistics need not be scary
This is not an answer to the student but to the professor who put the question together!!
This is a terribly misleading question!
You set up a situation where a number of samples are taken with dichotomous outcomes (GT 3 cups/day or LE 3 cups per day). This is a classic binomial distribution. which has parameters of p and n. Then you set up a situation where the student is lead to believe that a normal distribution is involved by asking for a mean and standard deviation, which are parameters for a normal distribution. Not a binomial.
Trying to justify the use of a simplifying / approximation solution and using a normal approximation is also wrong as the p value is very low (only .0403 using the typical biased estimator of s/n). This is ridiculously low and fails all the standard tests (test 1" When n * p and n * q are greater than 5 you can use approximation". n*p =5 so it fails) (test 2 " when np(1 − p) > 10" you can use normal approximation: n*p*q = 4.79 which also fails). So trying to trick the student into using a normal approximation with leading questions only produces confusion and bad results.
My advice to the student. Refuse to answer the question as phrased.
The distribution is binomial with a p of either 0.0403(biased) or .04 (unbiased Laplace estimate), with an n of 124. Normal approximation is not justified due to sample size and low p.