Mass of meson = 250m
m is massif electron
a= - 1.25x 10^14
vi =5x10^6
vf = 0
use vf^2 = 0 = (5x10^6)^2=2x1.25x10^14xD
Find D from here
For time taken to come to rest
vf =0 = vi- 1.25x10^14xt
plug in vi= 5x10^6
and find t
Alex J.
asked 11/28/21A meson, a subatomic particle having a mass 250 times that of an electron, is shot with a constant speed of 5.00 x 106 m/s into a region where an electric field causes a deceleration of 1.25 x 1014 m/s2.
(a) How far does the meason travel before coming to rest? (3 marks)
(b) How long does it take the meson to come to rest? (2 marks)
Mass of meson = 250m
m is massif electron
a= - 1.25x 10^14
vi =5x10^6
vf = 0
use vf^2 = 0 = (5x10^6)^2=2x1.25x10^14xD
Find D from here
For time taken to come to rest
vf =0 = vi- 1.25x10^14xt
plug in vi= 5x10^6
and find t
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.