2. The sum of 3 times a larger integer and 3 times a smaller integer is 15. When twice the smaller integer is subtracted to thrice the larger, the result is 20. Find the integers.

Answer 1

Hello Verkleide,

Let's call s the smaller integer and L the larger one. We will create an equation for each of the 1st two statements.

The sum of 3 times a larger integer and 3 times a smaller integer is 15:

3L + 3s = 15 ---- Equation #1

When twice the smaller integer is subtracted to thrice the larger, the result is 20

3L - 2s = 20 ---- Equation #2

You now have 2 equations and 2 unknowns. You can actually eliminate the variable L by subtracting equation #2 from equation #1:

5s = -5

Divide both sides by 5 and you get: s = -1

Now insert s=-1 into either equation. Let's use the 1st one:

3L + 3(-1) = 15 --->

3L - 3 = 15

I'll leave the last couple steps up to you, you got this!

Cheers.