Calculate the amount of heat released by 35 g of water at 100.°C as it touches the skin and cools to a body temperature of 37°C.

Answer 1

Specific heat of water = 4.184 J/gº

q = mC∆T

q = heat = ?

m = mass = 35 g

C = specific heat = 4.184 J/gº

∆T =change in temperature = 37º - 100º = -63º

q = (35 g)(4.184 J/gº)(-63º)

q = -9226 J = -9200 J (2 sig. figs.)

note the negative value since heat is being LOST by the water