Krugen K.

asked • 11/10/21

Can you show me how to find (1.016)^3 without calculator?

Anyone can do 1.0163 with a calculator but I am weak in decimal-related calculations and have to sit for exams that do not allow calculators. So can anyone show how to do this step by step without a calculator?

3 Answers By Expert Tutors

By:

Raymond B. answered • 01/13/22

Tutor
5 (2)

Math, microeconomics or criminal justice

Krugen K.

Thank you.
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02/18/22

Amanda K. answered • 11/10/21

Tutor
5 (6)

Certified and Experienced Elementary and Special Education Teacher

Krugen K.

Well anyone can figure cube is multiplying three times, but its this multiplication of the decimal values I have a problem with sadly.
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11/11/21

Amanda K.

For multiplying decimals, the easiest way is to do the multiplication like normal (ignoring the decimal point. So you would multiply 1016x1016 to get that answer. Then, look at the TOTAL number of places behind the decimal point, in this case six since you are multiplying 1.016 by itself. If it helps you, you can put the number of decimapl places by the problem. For example; 1.016 (3)x1.016(3)=answer (6 total decimal places; 3+3) Then take your answer and multiply it by 1.016. So your final answer will have 9 digits after the decimal point. I hope this clears up your question.
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11/11/21

Krugen K.

Sorry for the delayed response, i didnt check back in a while. Thank you very much
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11/21/21

Krugen K.

I didn't know this formula, thank you! Btw we add 1+ε here because it is 1 or we would use a different digit, like say (2.016)^3 = 2+3(01.16)?
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11/10/21

JACQUES D.

tutor
No, you would have to factor out a 2^3 so that you now have 8(1 +.016/2)^3 which would be 8(1+.024) approximately. You could use the full binomial formula for cubic 2^3 +3*2^2*.016 + 3*2*(.016)^2 + .016^3. Notice that the 1st two terms results in the same approximation. The reason you want the epsilon<<1 is to be able to ignore epsilon squared and epsilon cubed terms.
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11/10/21

Krugen K.

Ok thank you very much, now I fully understand.
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11/10/21

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