Help me answer this problem!!!

Question

The pressure of 4.85 L of an ideal gas in a flexible container is decreased to one-third of its original pressure, and its absolute temperature is decreased by one-half. What is the final volume of the gas?

Answer 1

P1V1/T1 = P2V2/T2 ... Combined Gas Law

P1 = P1

V1 = 4.85 L

T1 = T1

P2 = 1/3P1

V2 = ?

T2 = 1/2T1

Solving for V2, we have..

V2 = P1V1T2 / P2T1 = (P1)(4.85)(0.5T1) / 0.33P1)(T1)

V2 = 2.425 P1T1 / 0.33P1T1 = 2.425 / 0.33

V2 = 7.35 L