
Athena P.
asked 10/21/21Physics please if anyone can help
Mr. Herbert recorded the total flight time to be exactly 6.5 seconds using your knowledge of physics find out the following about the rocket :
A) the max height
B) find the initial velocity
C) Find the final velocity of the rocket before it hit the ground
1 Expert Answer

John David L. answered 10/21/21
Texas A&M Mechanical Engineer Grad and Lover of Physics
This is a 1 dimensional free-fall / projectile motion question.
A) Model the second half (t=3.25 to t=6.5) of the rocket's path from it's max height to the ground:
Max height = -Δh = -(1/2)gt2 = -(1/2)*(-10 m/s2)*(3.25 s)2 = 52.8 meters
B) Model both halves (t=0 to t=6.5) of the rocket's path from its initial launch to hitting the ground:
Δh = (1/2)gt2 + vot = 0
Solve for vo:
vo = (-(1/2)gt2)/t = -(1/2)gt = -(1/2)*(-10 m/s)*(6.5 s) = + 32.5 m/s
C) Model the second half of the rocket's path (t=3.25 to t=6.5). We should see that vo = - vf .
vf = vo + gt , where vo = 0 because it's at the top of its path.
vf = gt = (-10 m/s)*(3.25 s) = - 32.5 m/s
To double-check that our answer is correct, let's use conservation of energy:
∑Ei = ∑Ef
Ui = Kf
mghmax = (1/2)mvf2
hmax = vf2 / 2g = (32.5 m/s)2 / 2(10 m/s) = 52.8 meters.
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Luke J.
Athena, is this travel only vertical? No horizontal movement? Just up and down? This determines the solution path and can cause differing answers. Thank you.10/21/21