What is the concentration in %m/v of a 0.631 M aqueous solution of propylene glycol (MM = 76.09 g/mol)?

Answer 1

% m/v mean grams of solute per 100 mls of solution.

First we'll find grams of solute, propylene glycol (PG):

0.631 M = 0.631 mols/L

Assuming 1 L of solution, we have 0.631 mols PG x 76.09 g/mol = 48.01 g PG

The volume is 1 L = 1000 ml

So % m/v = g PG / 100 ml = 48.01 g PG/1000 ml x 100 ml = 4.80% m/v