Please give me the answer in full detail please!! Thank you so much!!

Question

The velocity of a car increases from 8m/s to 28m/s in 8s without a directional change. Calculate: 

a) its change of velocity:

b) its acceleration:

Answer 1

8 to 28 in 8

lot of eights. You're behind the 8 ball. so to speak, if that phrase is around these days.

a problem similar to what's the acceleration of a vehicle that goes from 0 to 60 in 3 seconds or the model?

v(0) = 8

v(8) = 28

v(8)-v(0) = 28- 8 = 20 meters per second = change in velocity

a= derivative of velocity

v = integral of acceleration

s(t) = (a/2)t^2 + (vo)t + so

s(8) = (a/2)(64) + vo(8)

v(8) = a(8) + vo

a(8) = a

s(0) = vo

v(0) = 8

a (0) = a

a = [v(8)-v(0)]/(8-0) = (28-8)/8 = 20/8 = 2.5 m/s^2 = acceleration

acceleration = 2 1/2 meters per second per second

at initial time t=0, v= 8

at time t=1 v= 8+2.5 = 10.5

at time t=2 v = 10.5 +2.5 = 13

at time t=3, v = 13+2.5 = 15.5

time t=4 v= 18

t = 5, v= 20.5

t = 6 v= 23

t = 7 v = 25.5

t = 8 v = 28