15-3x = x + 3 = EF
4x=12
x = 12/4 = 3
EF = x+3 = 3+3 = 6
Madison H.
asked 10/07/21E is the midpoint of DF,DE=15-3x, and EF=x+3,then EF= What the answers are 1, 3, 6, 12
15-3x = x + 3 = EF
4x=12
x = 12/4 = 3
EF = x+3 = 3+3 = 6
Jon S. answered 10/07/21
Patient and Knowledgeable Math and English Tutor
If E is the midpoint then DE = EF, so you can equate the two expressions for those lengths and solve for x:
15 - 3x = x + 3
12 = 4x
3 = x
substitute 3 for x in the expression for EF: x + 3 = 3 + 3 = 6
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