Toyin L. answered 10/03/21
Double Engineering Major-Masters in Mathematics-Teaching Math Right
If the random variable X has a Poison distribution then its mean µ = λ the parameter of a Poisson distribution. a) For a Poisson distribution the probability Pr(X=n) = ( e–λ λn) / n! (Note n! = 1*2*3 ...*n and 0! = 1)
In this problem μ = λ = 0.34
So the probability Pr(X = 0) = (e-0.34* 0.340) / 0! = e-0.34 = 0.71177
b) Pr(X > 0) = 1 - Pr(X = 0) - 1 - 0.71177 = 0.28823
Hamza A.
Thank you so much! much appreciated !10/03/21