...Suppose a 57.76-kg package on

Question

Suppose a 57.76-kg package on the roller belt conveyor system is moving at 0.738 m/s. What is its kinetic energy?

Answer 1

For this problem we should start by listing the "Givens" -- Mass = 57.76 Kg , Velocity = 0.738 meters/second.

Now we should consider what the question itself is asking us -- it is asking "what is the Kinetic Energy" -- well, we should note that the formula for KE = 1/2 * m * v^2 -- so lets plug in and see what we obtain as an answer.

KE = (1/2) * (57.76 kg) * (0.738)^2

KE = (0.5) * (57.76) * (0.544) = 15.73 Joules (Joules is the SI unit for energy and as long as the mass is in Kg, and the velocity is in meters/second, we would always use the unit of Joules, unless indicated otherwise)