J.R. S. answered 09/23/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
530,000 mg x 1 g / 1000 mg x 1 cm3 / 19.3 g = 27.5 cm3 = volume of the bar
Volume = L x W x H
27.5 cm3 = 5.2 cm x 2.1 cm x H
H = 2.5 cm
Chad J.
asked 09/22/21A gold bar has a mass of 530,000 mg. The bar has a length of 5.2 cm a width of 2.1 cm and a density of 19.3 g/cm^3 Determine the height of the bar in millimeters. Show all work.
J.R. S. answered 09/23/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
530,000 mg x 1 g / 1000 mg x 1 cm3 / 19.3 g = 27.5 cm3 = volume of the bar
Volume = L x W x H
27.5 cm3 = 5.2 cm x 2.1 cm x H
H = 2.5 cm
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