x=4−5t,
y=4t−5,
z=−3−4t.
The directing vector of the line is u = < -5 , 4, -4 >
For t = 0 gives us the point P ( 4, -5, -3 )
Dianz S.
asked 08/15/21Suppose a line is given by the system of equations
x=4−5t,
y=4t−5,
z=−3−4t.
Then the vector and point that were used to define this line were
v- =
p =
x=4−5t,
y=4t−5,
z=−3−4t.
The directing vector of the line is u = < -5 , 4, -4 >
For t = 0 gives us the point P ( 4, -5, -3 )
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