Roger N. answered 08/09/21
. BE in Civil Engineering . Senior Structural/Civil Engineer
Solution:
Vector a can be written as a→ = 8i+10j+4k , and unit vector of a is ua = a→ / | a|
where the magnitude |a| = √( 82+102+42) = √180 = √(36x5)= √36 . √5 = 6√5
ua = 8i + 10j + 4k / 6√5 = (8/6√5)i + ( 10/6√5)j + ( 4/6√5)k = ( 4/3√5) i + (5/3/√5) j + (2/3√5) k rationalize to get rid of the √ from the denominator multiply by √5 / √5 for all terms and simplify you get:
ua = (4√5/15) i + (√5 / 3) j + ( 2√5/15) k