Inactive Tutor answered 07/21/21
7x + 7(x+13) = 945
mph x time = distance
7x + 7x = 945 - 91
14x = 854
x = 854/14 = 61 mph for slower bus
x+13 = 74 mph for faster bus
in 7 hours they're 7 times (61+74) = 7(135) = 945 miles apart
Malik A.
asked 07/21/21Two buses leave a station at the same time and travel in opposite directions. One bus travels 13
mih
faster than the other. If the two buses are 945
miles apart after 7
hours, what is the rate of each bus?
Inactive Tutor answered 07/21/21
7x + 7(x+13) = 945
mph x time = distance
7x + 7x = 945 - 91
14x = 854
x = 854/14 = 61 mph for slower bus
x+13 = 74 mph for faster bus
in 7 hours they're 7 times (61+74) = 7(135) = 945 miles apart
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