1. How many grams of Acetic acid are needed in 10L solution of 0.1M concentration?

Question

To make 10 L of a 0.1 M acetic acid solution, you would need to add 60.0 grams of acetic acid and then bring the volume to a total of 10 L.

C2H4O2

Find moles first.

Molarity = moles of solute/Liters of solution

moles C2H4O2 = molarity/Liters solution

moles C2H4O2 = 0.1 M/10 L

= 0.01 moles C2H4O2

-----------------------------------now, molar mass time moles

0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2)

= 0.60 grams acetic acid needed

Answer 1

You have the correct answer. I presume you were asking someone to double-check your work?