If log(base a)b^2=5;
2*logab = 5
logab = 5/2
a5/2 = b or; a = b2/5
logba2 = 2*logba (lets plug a = b2/5 in to the equation)
2*logbb2/5 = 2*2/5 =4/5
hope that helps
Elaine L.
asked 07/16/212*logab = 5
logab = 5/2
a5/2 = b or; a = b2/5
logba2 = 2*logba (lets plug a = b2/5 in to the equation)
2*logbb2/5 = 2*2/5 =4/5
hope that helps
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