Yefim S. answered • 06/15/21

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1.uv = 6 - 2k - 7 = 0; k = - 1/2.

2.2k - 6 + 2k + 2 = 0 and k - 1 - 2k + 2 = 0

4k - 4 = 0 k = 1 and k = 1

So, k = 1

Kam S.

asked • 06/15/21- Determine the value of k such that u and v are orthogonal. u = [2, k, -1] and v = [3, -2, 7]
- Determine the value(s) of k such that (2k, 3, k+1) x (k-1, k, 1 = (1, -2, 2)

The x stands as a tip to do cross-product.

(Even though they use the same variables they're two entirely different questions)

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Yefim S. answered • 06/15/21

Tutor

5
(20)
Math Tutor with Experience

1.uv = 6 - 2k - 7 = 0; k = - 1/2.

2.2k - 6 + 2k + 2 = 0 and k - 1 - 2k + 2 = 0

4k - 4 = 0 k = 1 and k = 1

So, k = 1

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Kam S.

Thank you!06/15/21