Kitty C.

asked • 06/09/21

2 NABr + Ca(OH)2 = CaBr2 + 2 NaOH What was the initial mass of calcium hydroxide for a reaction that produced 52.9 g of NaOH?

Grateful for any help given!

1 Expert Answer

By:

J.R. S. answered • 06/09/21

Tutor
5.0 (145)

Ph.D. University Professor with 10+ years Tutoring Experience
About this tutor ›
About this tutor ›

Look at the balanced equation and see what the mole ratio is between Ca(OH)2 and NaOH.

It takes 1 mol Ca(OH)2 to produce 2 moles of NaOH.

2NaBr + Ca(OH)2 ==> CaBr2 + 2NaOH

So, now we must find the moles of NaOH represented by 52.9 g NaOH. Once we have that, we can determine the moles of Ca(OH)2 that was used to make that and then convert moles to grams.


moles NaOH produced = 52.9 g NaOH x 1 mol NaOH / 39.99 g = 1.32 moles NaOH

moles Ca(OH)2 needed = 1.32 mols NaOH x 1 mol Ca(OH)2 / 2 mols NaOH = 0.661 mols Ca(OH)2

Converting this to grams, we have...

0.661 mols Ca(OH)2 x 74.09 g Ca(OH)2 / mol = 49.0 g Ca(OH)2

Upvote • 1 Downvote
More
Report

Kitty C.

Thank you so much!
Report

06/09/21

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.