
Jack L. answered 06/06/21
PhD in Electrical Engineering and 12 years as Math professor
With 10% simple interest, you gain 10% of your original investment every year.
So, if your initial amount is P, then at the end of each year you will have
10% of your original investment added (that's the same amount of dollars
added each year.
Year Amount
1 P + 0.10P
2 P + 0.10P + 0.10P = P + 2(0.10)P
3 P + 0.10P + 0.10P + 0.10P = P + 3(0.10)P
N P + NP(0.10)
With 5% compound interest, at the end of each year you will have increased
by 5% OF THE PREVIOUS YEAR's amount.
Year Amount
1 P + 0.05P = 1.05P
2 1.05 times the amount you had at the end of year 1, which was 1.05P,
so you have 1.05(1.05)P = (1.05)^2)P (1.05)^2 is 1.05 squared
3 1.05 times the amount you had at the end of year 2, which was (1.05)^P,
so you have (1.05)^3)P
N (1.05)^NP
So say P=1 dollar.
At year N, 10% simple interest you will have 1+N(0.10),
while with 5% compound interest you will have (1.05)^N dollars.
By 27 years, the (1.05)^N will finally exceed the 1+N(0.10).
At N=27, (1.05)^27 = 3.733 while 1+ 27(0.10)= 3.700