Mike D. answered • 06/05/21
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Well if the width is w and l is the length then 2w + 2l = 200 so w+l = 100
Area = lw = 2400
l = 100 - w
w (100-w) = 2400
100w - w2 = 2400
w2 - 100w + 2400 = 0
you can factorise this or use the quadratic formula to solve for w, then knowing w you can find l
Mike D.
Lia, these cannot be right. You can't have a negative length ! It factorises to (w-60) (w-40) so w can be 60 or 40, giving l = 40 or 60. So length = 60, width = 40 is possible. Perimeter = 60 + 40 + 60 + 40 = 200 and area = 60 x 40 = 2400 ft^2
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06/05/21
Mike D.
If you can't factorise it you can draw y = x^2 - 100x + 2400 on Desmos and find the x values where it crosses the x-axis.
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06/05/21
Lia M.
I got -20 and 120 idk if that even close to right tho06/05/21