Suppose that sin0=2/9 and that π/2 < 0 < π . Find the values of sin0,cos0 ,csc0 ,sec0 , and cot0.

Question

Suppose that tan0=2/9 and that π/2 < 0 < π . Find the values of tan0,cos0 ,csc0 ,sec0 , and cot0. 

tan0=?

cos0=?

csc0=?

sec0=?

cot0=?

Answer 1

sinx = 2/9 = opposite side over hypotenuse, o/h

adjacent side squared = a^2 = hypotenuse squared minus opposite side squared = 9^2-2^2 = 81-4 = 77

adjacent side = a = -sqr77

cosx = a/h = -sqr77/9

secx = -h/a = 9/sqr77

cscx = h/o =9/2

tanx = -o/a = -2/sqr77

cotx = a/o = -sqr77/2